(X^2-5)+(x+20)=(x^2+1)-15

Solution for (X^2-5)+(x+20)=(x^2+1)-15 equation:

(X^2-5)+(X+20)=(X^2+1)-15

We move all terms to the left:

(X^2-5)+(X+20)-((X^2+1)-15)=0

We get rid of parentheses

X^2+X-((X^2+1)-15)-5+20=0


We calculate terms in parentheses: -((X^2+1)-15), so:

(X^2+1)-15

We get rid of parentheses

X^2+1-15

We add all the numbers together, and all the variables

X^2-14

Back to the equation:

-(X^2-14)


We add all the numbers together, and all the variables

X^2+X-(X^2-14)+15=0

We get rid of parentheses

X^2-X^2+X+14+15=0

We add all the numbers together, and all the variables

X+29=0

We move all terms containing X to the left, all other terms to the right

X=-29